That's such a text book answer, you square!
Lets get the ball rolling...
Lets drop the barometre from the top of the building and time how long it takes to hit the ground.
S = displacement U= initial velocity a = acceleration (9.81ms^-2) t = time.
S=ut+0.5at^2
We know u is zero, a is 9.81 and that t can be measured. Plug it all into the formula and you get the height.
There are more things you can add. For example the air resistance, but I haven't reached that part of my course yet![]()
I did refer to my first post in an edit that allowed some basic equipmentWe wern't given a stop watch, photo finish equipment, PLUS, as it accelerates its air resistance increases, unless you work out its drag co-efficient and also lug the new air resistance formula into the already existing UVATS formula then it is going to be incorrect.
You measure the length of the barometer, then use the barometer to measure the building.
Now you've broken a perfectly good barometer, thus raising the lab fee for everyone else. Thanks a lot.Lets drop the barometre from the top of the building and time how long it takes to hit the ground.
Exactly what my physics lecturer said.Go to the designer of the building and ask him the height in exchange for the barometer
Secure the barometer in an upright position on the ground, and measure both its height and the length of its shadow. Then measure the length of the building's shadow.
Do a little trigonometry and presto, you have the building's height.
take the barometer, put it on the ground, measure the reading, lift it 5 feet off the ground, record the settings, go to the top, record the settings, and then calculate how far you could throw a goat. burn your readings, get a ruler, get bitten by a radioactive spider, and measure the height using the written records you got from the buildings designer.
At night, throw the barometer through the window of the county's Office of Public Records, then steal the blueprints.
Finally! Some good answers here 👍
Also, tie a piece(s) of string to the barometre and lower it from the roof of the building to the ground and measure the string.
Use the markings on the barometre as a protractor and move a set distance from the building and measure the angle to the top of the building. Then use trig'. (Abit more far fetched I admit.)
Exactly what my physics lecturer said.![]()
This is all based on the 'easy' mechanics stuff, it's if/when you start doing quantum and quarks it gets difficult!Nice to see what I am getting myself into this year, in my college physics lessons.
And you will be answering pointless questions like this, and the airplane/conveyor question that's in another thread. The only difference is that your teachers will want "real" answers.Nice to see what I am getting myself into this year, in my college physics lessons.
Quantum mechanics is far more interesting than throwing a ball off a moving train and figuring out where it landsExigeExcelThis is all based on the 'easy' mechanics stuff, it's if/when you start doing quantum and quarks it gets difficult!
This is all based on the 'easy' mechanics stuff, it's if/when you start doing quantum and quarks it gets difficult!
Not really. This question was merely asked by my lecturer when 6 people turned up for a lecture near the end of term. Yes, I was one of those 6.And you will be answering pointless questions like this, and the airplane/conveyor question that's in another thread. The only difference is that your teachers will want "real" answers.
Not to me. I'd much rather be able to throw a ball at the head of someone I dislike from a moving object than learn about things that while (strongly) proven are taught in an almost theoretical way. But it's different for everyone.Quantum mechanics is far more interesting than throwing a ball off a moving train and figuring out where it lands![]()
But how long's a piece of string?EvanAlso, tie a piece(s) of string to the barometre and lower it from the roof of the building to the ground and measure the string.