- 3,941

- Connecticut

- Ridley-X4

If my math is right, then if I travel for 67.2k miles in a Hyundai Ioniq Hybrid Blue, then every bit of travel after that will be saving me money in fuel versus if I had bought a Hyundai Kona SE.

Allow me to explain my math. I took the combined MPG of each vehicle, which was 59 for the Ioniq Hybrid Blue (rounded up to 60 for convenience) and 35 for the Kona SE. I also took their respective MSRPs into account, being $23.4k for the Ioniq Hybrid Blue and $21k for the Kona SE. I also assume the average price of fuel is $3.00 per gallon.

The price of fuel alone can be represented as (m/(m/g))*3, where (m/(m/g)) is the number of gallons I’d be using, or in other words, the mileage divided by the miles per gallon of each vehicle. The price of fuel is added to the MSRP of the corresponding vehicle, meaning the resulting expression should be as follows:

23.4k + ((m/60)*3) = 21k + ((m/35)*3)

I am trying to figure out how many miles I’d need to travel in the Ioniq Hybrid Blue to start saving money on fuel. Is 67,200 miles correct?

Allow me to explain my math. I took the combined MPG of each vehicle, which was 59 for the Ioniq Hybrid Blue (rounded up to 60 for convenience) and 35 for the Kona SE. I also took their respective MSRPs into account, being $23.4k for the Ioniq Hybrid Blue and $21k for the Kona SE. I also assume the average price of fuel is $3.00 per gallon.

The price of fuel alone can be represented as (m/(m/g))*3, where (m/(m/g)) is the number of gallons I’d be using, or in other words, the mileage divided by the miles per gallon of each vehicle. The price of fuel is added to the MSRP of the corresponding vehicle, meaning the resulting expression should be as follows:

23.4k + ((m/60)*3) = 21k + ((m/35)*3)

I am trying to figure out how many miles I’d need to travel in the Ioniq Hybrid Blue to start saving money on fuel. Is 67,200 miles correct?

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