Great find
@KinLM!
Aren't we comparing terminal velocities here? A quick rearangement of the relevant formulas shows that:
At
terminal velocity v_t the accelerating force F and the drag force cancel each other:
1/2 rho v² Cd A = F
=>
v_t = sqrt( 2 F /(rho Cd A) )
The density of air rho depends on temperature T like
this:
rho(T) = p / (R T)
p is pressure, R is the specific gas constant
Plugging it all together we get a sublinear dependance of terminal velocity on temperature:
v_t = C sqrt(F T)
with C = sqrt((2 p R)/(Cd A))
Maybe i'm ignoring something important, i'm not an aerodynamics expert.
I cannot make this out in the plot of
@MadMax's data, maybe we need more data:
View attachment 423874
EDIT: one way to test the formula might be to 'extend' the temperature range by using a car with the same aerodynamics but a different engine like the Opel Speedster/Turbo and pretend they generate the same force, but at a different temperature. This might show the square root dependence...