Equation to determine PP, roughly

  • Thread starter Thread starter gamerdog6482
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I wish i took more notice in math class, it is way over my head!

I'll dumb it down a little bit:

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Where p is power, t is torque, w is weight, F sub d is front downforce, R sub d is rear downforce, M sub F sub d is front minimum downforce, and M sub R sub d is rear minimum downforce.
 
gamerdog6482
I recently came across an equation that, when use correctly, gives you a number close to your car's PP.

PP = 259*(power*torque/weight)^(0.15) + (Fd+Rd)/2 - (MFd+MRd)/2

where Fd and Rd are the current front and rear downforce, and MFd and MRd are the minimum front and rear downforce.

Let's try it out with a fully tuned Jaguar E-Type.

Plug in the numbers and you get 259*(440*240/1038)^.015+([{0+0}/2]-[{0+0}/2])
That simplifies to 259(440*240/1038)^0.15
That simplifies to 259(157.26)^0.15
That simplifies to 259(2.13)
Which ends up being, low and behold, ~553.
Actual PP for the car is 513.

Keep in mind that the equation does not factor in weight distribution, which is most likely the reason for the higher result.

EDIT: Here is a better looking version:

I noticed root 2 in the working, where in the formula it's just dividing by 2, so which one is wrong? :p
 
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