Homework Math Help (Math Nerds Unite)

Messages
9,899
solve right triangle ABC given that A= 30 degrees, C= 90 degrees, and a = 8

I need to know HOW to do it, not just the answers
using tan and cos and all that garbage


PLEASE HELP
 
What do you want to know? What the angle of B is or the length of b and c?
 
B=60
a=8
b=8 square root of 3
c=16
Per my oldest son.
I have no idea what it means but that is the answer.
 
Well, B = 60 since the angles of a triangle must add up to 180 degrees, and 90 + 30 (the other angles) add up to 120. 180-120=60.

Side b = 8. Common sense. Since a squared plus b squared = c squared, "c squared" (the hypotenuse) must equal the square root of 64, which I think is 8 route 13 as Gil said.

Ask Klos, he did this last year.
 
another one
 

Attachments

  • 12121.jpg
    12121.jpg
    53.4 KB · Views: 78
Doug's response is exactly it... nothing more to that problem.

If you want to "hear it as many times" as you can:

Well, B = 60 since the angles of a triangle must add up to 180 degrees, and 90 + 30 (the other angles) add up to 120. 180-120=60.

Side b = 8. Common sense. Since a squared plus b squared = c squared, "c squared" (the hypotenuse) must equal the square root of 64...


:D

Is there anything in particular that doesn't make sense once that's analyzed? (I took geometry last year though, so don't expect too much out of me... :smilewink)

[edit]: The problem that you just posted is actually easier to solve... since the angles are already supplied. :)
 
I dont need common sense answers though, thats not good for the teacher... she needs to know HOW i got it useing cos and tan and all that crap.. i need the method, not the answers
 
Dammit!!, I know exactly how to do this, but its somewhere deep down in my brain and I cant remember it!! :mad: Something to do with negative cos/tan/sin ??
 
sin=opposite/hypotenuse
cosin=adjacent/hypotenuse
tan=opposite/adjacent
 
Quite honestly, I don't remember anything other than what I've already posted... sorry I can't help any farther than that.

I think your friend needs to stay awake during his classes. ;)
 
Theta, The eighth letter of the Greek alphabet.
Used for any unknown angle in a triangle (or any other shape).

Thats just my interpretation of it.
 
A jet flying at a height of 2100 feet spots an enemy rocket launcher directly in front of the plane at an angle of deoression of 15* How many feet will the jet fighter travel before it flies dierctly over the rocket launcher? round the answer to the nearest hundred




How do I do this

What are the operations i have to go through
 
Well this is Trignometry, and these are my notes when we started the topic. This is how to find lengths of right-angled triangles.
I'll work out your answer in the next post, hopefully :)
 

Attachments

  • helpwithtrig.jpg
    helpwithtrig.jpg
    66.4 KB · Views: 64
Lets Hope I dont screw this up:

|
| 2100ft (O)
/15*_________|
(A)
You have the Opposite and you want the Adjacent
So:
* * * *
SOHCAHTOA

You want to use Tan.

Tan (Theta)= O
A

So: 2100 = tan15*
A

So: A = 2100xtan15* = 31500

My answer is 31500feet. But I wouldnt be suprised if I was wrong... One of these 'older' members would blitz me in Maths...
 
Well I tried to make it easy to read but the spacing in the posts doesnt work and the html spacing code wont work so there you have it...
 
Back