- 379
- PNW
- Zenmervolt
I've heard it described this way: torque will get you there quicker. HP will get you to a higher top speed. So if you have 100 HP and 200 Torque vs 200 HP and 100 torque example one will have a lower top speed, but 0-60, 0-100 and 0-top speed will be quicker than example two. However if you're running a high speed track like Daytona or Le Sarthe you will probably do better with the high HP as opposed to short tight tracks where acceleration is king.
Not accurate. Not even close.
100 hp with 200 ft-lbs will mean that torque falls off massively at higher RPM. In fact, to have only 100 hp with 200 ft-lbs of torque would mean that torque peaked at 2,626 RPM (100 = 200*2626/5252), with torque falling off massively after that point to only 100 ft-lbs at 5252 RPM. The engine would be a peaky pain in the ass with almost zero usable RPM range. Basically, it would be an old-school diesel. And we all know how well those old diesels would accelerate...
Now, the engine with 100 ft-lbs and 200 hp would have to rev to 10,504 RPM where it would be making 100 ft-lbs of torque and 200 hp. Torque would climb steadily from idle to HP peak.
Additionally, the second engine can take massive advantage of gearing, while the first cannot. Let's say that we need an output shaft spinning at 2,626 RPM. For the first engine, that's a 1:1 gear ratio. No torque multiplication, so the result is that the output shaft sees 200 ft-lbs of torque and 100 hp. For the second engine, however, that's a 4:1 gear ratio. 4x torque multiplication, so the output shaft gets 400 ft-lbs of torque and 200 hp.
The second engine will accelerate much faster than the first and it will have a higher top speed. It's all in the link I posted earlier. HP at high RPM is what you want so you can take advantage of gearing. Low-rpm torque can make a car feel "effortless", but high RPM horsepower will accelerate faster unless someone terribly buggers the gearing.