No_OBsT33R's LSD Calc UPDATED Version 1.1

[chuyler1]

alright, i'll be quiet and wait to see some progress.

 

[gt5 brad gt5]

Don't mean to sound like an ass or anything. All of these pages debating about LSD's, isn't this abit far for a game, even for GT5 I feel.But I've followed this debate all throughout its pages.

I appreciate the help from the OP, thankyou for sharing your knowledge.

Now I am a noob when it comes to LSD's etc but I am looking foward to the developments that are going to be made to this calculator.

Just another question. Will this make your car go faster or will it just make it feel better going through a corner?

cheers guys, some clever sods here 👍

 

[No_OBsT33R]

You need to explain, how you can say that they both have the same amount of power at the wheels.

If yah don't know, now you know.

I found my old text books, I can use them to better explain what seems hard to understand from my explanations. I'll just post pics out of it, so it's all FACT, not my opinion.

 

[Adrenaline]

Quote me where I mentioned a corner.
If I say 2+2 is 4, you can't disprove me, by reciting the alphabet.
I gave you a very specific scenario, you refused to prove your theory, so I left your thread alone, and now you're trying to continue the argument, to draw me back in, because you love the attention.

An Open diff and a brake stand.
When the "resisting force" is the exact same.
Which is why I was very specific about my scenario.

 

[No_OBsT33R]

Quote me where I mentioned a corner.
If I say 2+2 is 4, you can't disprove me, by reciting the alphabet.
I gave you a very specific scenario, you refused to prove your theory, so I left your thread alone, and now you're trying to continue the argument, to draw me back in, because you love the attention.

An Open diff and a brake stand.
When the "resisting force" is the exact same.
Which is why I was very specific about my scenario.

Nice deflection. You asked how the 2 wheels get the same power, I answered. You don't believe me, so I show you out of the text book from my Mechanics class (had to dig around for them). You act like you didn't realize we were talking about corners, but you knew. Good try.....

""Originally Posted by No_OBsT33R
I'll go in depth in a sec, but power is always equal between both wheels at all times in open, closed, and LSDifferentials.""

""Originally Posted by Adrenaline
You need to explain, how you can say that they both have the same amount of power at the wheels.""

Moving to your scenario...

Your scenario is Pretty dumb, and I already explained it = smoke and no go. You go off rambling...

I'll go over it again if I wasn't clear.

However, To be specific the tires are NEVER under the exact same conditions NEVER, that's just impossible like 2 identical snow flakes.

While resistance will be relatively equal one side will give before the other if they are both forced beyond their capabilities, when it goes, all useable power is gonzo. It is utterly impossible your scenario of exact same conditions on either side. Literally impossible, nice try though...

Let's see what happens under realistic conditions, that aren't failed attempts from Adrenalin to prove the No_OB wrong...

RWD as long as the front wheels hold you in place & you have the Torque to overpower the drive wheel brakes, Open diff, foot on brake & foot on gas, one wheel smokes, no power moving car forward from the wheel with grip..

FWD with the hand brake pulled & as long as the rear wheels hold you in place, Open diff, foot on gas, one wheel smokes..... Again no power moving forward from the wheel with grip..

Is that really that hard to understand?

Have you never driven a car before? That's basic stuff buddy....

LSD both wheels spin in both cases making a smoke show AKA a burnout with both tires not just one, the car still doesn't move as it's either held by the front in the case of a RWD or the rear in the case of a FWD.

You need to invent an impossible scenario to try and prove me wrong? Why you so bent up on proving me wrong? Get over it, Adrenalin your done...

 

[Adrenaline]

It's the same thing every time we've butt heads. You make a claim, I disagree, and you always put the burden of proof on me, despite the fact you're the one making the outrageous claims. Then even when I provide the proof, you claw and cling to any type of cop out you can, continuing to live in la la land. So you're right about one thing, I am done.

 

[No_OBsT33R]

It's the same thing every time we've butt heads. You make a claim, I disagree, and you always put the burden of proof on me, despite the fact you're the one making the outrageous claims. Then even when I provide the proof, you claw and cling to any type of cop out you can, continuing to live in la la land. So you're right about one thing, I am done.

Proof?? Where, your impossible scenario, I already spit back in your face? Yeah you describe yourself real well Mr Cop-out-king..

You asked the question, I answered. You proposed an impossible scenario to simply to prove me wrong, I not only expose the inaccuracy & the fact the scenario is impossible, I explain what would happen and why in a realistic scenario. Cop out? Where?

Cling away there Buddy. Your the only one copping out. What a joke.

You are Done...

No_OB

 

[Will27]

Right, so I tried and I tried, to resist coming back to this thread, but I've failed.

I can't simplify this scenario any further than I have:

A car with an open diff
The same tires
The same brakes
The same asphalt beneath said tires
and
The same power being applied to each wheel (your theory)

Does a burn out and only a single tire spins...

Explain how this is possible.

You can't, because it ISN'T possible.
It is physically, logically and mathematically impossible
for both tires to have the same force acting against them
with the same power being applied to them
and end in 2 different results.

To explain:

Open diff the same torque is applied to both wheels.

Newtons third law.. Every action requires an equal and opposite reaction. The ground applies the same torque as each wheel in the opposite direction.

More weight is on the outside wheel, more grip.
Less weight on inside wheel, less grip.
Less torque is applied to both wheels.

When the ground cannot provide adequate reaction torque(grip), your wheels spin. If this happens to one wheel, then this means less torque would be applied to that wheel. But the open diff cannot do this. It must reduce torque to the other side as well.
This can happen in 2 ways: The wheel with no grip can spin, with no reaction torque
Reduce the torque from the engine to a point where the ground can provide sufficient reaction torque (traction control for example)

This is what happens to an open diff in a powerful car accelerating out of a corner. The inside wheel has less weight pressing down on it, therefore less grip, meaning the ground cannot apply enough torque in the opposite direction. The inside wheel spins.


In my opinion, someone here needs to translate “textbook talk” to real life. Reading this thread is like going back to school with teachers that can only read the textbook, can’t actually teach it.

 

[Motor City Hami]

Right, so I tried and I tried, to resist coming back to this thread, but I've failed.

To explain:

Open diff the same torque is applied to both wheels.

Newtons third law.. Every action requires an equal and opposite reaction. The ground applies the same torque as each wheel in the opposite direction.

More weight is on the outside wheel, more grip.
Less weight on inside wheel, less grip.
Less torque is applied to both wheels.

When the ground cannot provide adequate reaction torque(grip), your wheels spin. If this happens to one wheel, then this means less torque would be applied to that wheel. But the open diff cannot do this. It must reduce torque to the other side as well.
This can happen in 2 ways: The wheel with no grip can spin, with no reaction torque
Reduce the torque from the engine to a point where the ground can provide sufficient reaction torque (traction control for example)

This is what happens to an open diff in a powerful car accelerating out of a corner. The inside wheel has less weight pressing down on it, therefore less grip, meaning the ground cannot apply enough torque in the opposite direction. The inside wheel spins.


In my opinion, someone here needs to translate “textbook talk” to real life. Reading this thread is like going back to school with teachers that can only read the textbook, can’t actually teach it.

+1

Finally someone who lays out a simple, logical, proven description.

 

[No_OBsT33R]

Thanks Will, I'm not a teacher, did the best I could with a few more interested in proving me wrong (still waiting) then actually interested in understanding. That's life.

No_OB