gamerdog6482
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- Gamerdog6482
I recently came across an equation that, when use correctly, gives you a number close to your car's PP.
PP = 259*(power*torque/weight)^(0.15) + (Fd+Rd)/2 - (MFd+MRd)/2
where Fd and Rd are the current front and rear downforce, and MFd and MRd are the minimum front and rear downforce.
Let's try it out with a fully tuned Jaguar E-Type.
Plug in the numbers and you get 259*(440*240/1038)^.015+([{0+0}/2]-[{0+0}/2])
That simplifies to 259(440*240/1038)^0.15
That simplifies to 259(157.26)^0.15
That simplifies to 259(2.13)
Which ends up being, low and behold, ~553.
Actual PP for the car is 513.
Keep in mind that the equation does not factor in weight distribution, which is most likely the reason for the higher result.
EDIT: Here is a better looking version:
PP = 259*(power*torque/weight)^(0.15) + (Fd+Rd)/2 - (MFd+MRd)/2
where Fd and Rd are the current front and rear downforce, and MFd and MRd are the minimum front and rear downforce.
Let's try it out with a fully tuned Jaguar E-Type.
Plug in the numbers and you get 259*(440*240/1038)^.015+([{0+0}/2]-[{0+0}/2])
That simplifies to 259(440*240/1038)^0.15
That simplifies to 259(157.26)^0.15
That simplifies to 259(2.13)
Which ends up being, low and behold, ~553.
Actual PP for the car is 513.
Keep in mind that the equation does not factor in weight distribution, which is most likely the reason for the higher result.
EDIT: Here is a better looking version:
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