Let's have some fun with math!

[Firebird]

Originally posted by Crayola
Sorry joey but thats not quite right.
It should be (x+3)^2 = 16
X + 3 =4
X = 1

Joey was perfectly correct. You missed -7 as one of the possible answers.

 

[Firebird]

Originally posted by Crayola
isn't 18 5m - 3/m+3 ?

m+9/m+3 - -4m-6/m+3 = 5m+15/m+3 = 5(m+3)/m+3 = 5(m+3/m+3) = 5(1) = 5

 

[Slick6]

Nevermind.

 

[Jpec07]

wow, you can't even do those? Why are you in an Algebra class? My suggestion is to learn how to factor and eliminate terms and then use that in your math (instead of trying to get us to do it for you). But, if you would like me to explain how to factor polynomials to you I will give you a simple formula-set that will help:

Ax^2 + Bx + C = (Qx + R)*(Sx + T)

therefore...

A = Q*S
B = S*R + Q*T
C = R*T

it follows that...

Ax^2 + Bx + C = Q*S*x^2 + (Q*T + S*R)*x + R*T = (Qx + R)*(Sx + T)

 

[Crayola]

Originally posted by Firebird
Joey was perfectly correct. You missed -7 as one of the possible answers.

Meh, I suppose. Its only because I dont have a button that's "plus or Minus" because then x+3 = +4,-4 and yer, I know he's right.

 

[Sage]

Erm, why would you need a +/− button to solve that problem? Surely you don't need a calculator to solve −4 − 3?

 

[oosacker]

I dislike maths.

 

[Event]

i gotz an 86 on my math final, 92 in the class and somehow it's considered an A-....