Will Famine ever create a thread in the "Ask GTPlanet" forum?

[kennythebomb]

There's no shortage of questions Famine could ask.

 

[wfooshee]

n

Excellent!!!

 

[TVRKing]

OOooooh. I've got a question for Famine that would test his large IQ to bursting point (and no, it's not about waffles).

What was the serial number range on a 1964 Fender Stratocaster, and where was it situated?

*Edit - I though it was <><> for infinity, not n

 

[Omnis]

n

Hmmm... Brainstorm:

Though they have the potential to be the same, which is greater? n or n^n?

 

[Sage]

Depends on the value of n.

If n>0 || n<=-2, then n^n>n.

If n>-2 && n<0 && n!==-1, then n^n==Oh_crap

If n==0 || n==-1, then n^n==n.

 

[Omnis]

but n can be nything. That is the mystery...

 

[Keef]

Sage, you should post some up that cover nything.

 

[Sharky.]

In that case, n is neither less, equal to, or more than n^n.

 

[wfooshee]

How is it that Famine posts A SINGLE LETTER and it suddenly gets this complicated. Do we really want him to ask a question??!??!?!?!!

 

[skip0110]

Depends on the value of n.

If n>0 || n<=-2, then n^n>n.

If n>-2 && n<0 && n!==-1, then n^n==Oh_crap

If n==0 || n==-1, then n^n==n.

But what if n<=-2, then you can get something imaginary, so is an imaginary number bigger than a real number?


(e.g. n = -3.5)

 

[Omnis]

But what if n<=-2, then you can get something imaginary, so is an imaginary number bigger than a real number?


(e.g. n = -3.5)

👍

 

[DuckRacer]

n

*Edit - I though it was <><> for infinity, not n

Though they have the potential to be the same, which is greater? n or n^n?

Depends on the value of n.

If n>0 || n<=-2, then n^n>n.

If n>-2 && n<0 && n!==-1, then n^n==Oh_crap

If n==0 || n==-1, then n^n==n.

but n can be nything. That is the mystery...

In that case, n is neither less, equal to, or more than n^n.

But what if n<=-2, then you can get something imaginary, so is an imaginary number bigger than a real number?


(e.g. n = -3.5)

I have a headache because of you all. Thanks!

 

[fyfee]

Infinity is represented as a + or - sidewards 8.

 

[Sage]

But what if n<=-2, then you can get something imaginary, so is an imaginary number bigger than a real number?

Oh, you&#8217;re right. Let&#8217;s revise the formulae:

If n>0 && n!==1, then n^n>n.

If n==0 || n==1, then n^n==n.

If n<0, then screw it.

 

[Sakiale]

....

I do believe that only a select few of you know exactly what the hell you are doing. Do you realize that if "n>0 && n!==1, then n^n>n" is not a valid equation? And do you realize that if "n==0 || n==1, then n^n==n", then the very existence of this universe is impossible?

 

[skip0110]

Sage: 👍

....

I do believe that only a select few of you know exactly what the hell you are doing. Do you realize that if "n>0 && n!==1, then n^n>n" is not a valid equation? And do you realize that if "n==0 || n==1, then n^n==n", then the very existence of this universe is impossible?

Are YOU sure YOU know what the hell you are doing?

n>0 && n!==1, then n^n>n -----> literally, If n is bigger than zero and not equal to 1, then n^n is bigger than n. Sounds fairly true to me.

 

[Sakiale]

No.

But are those equations actually equations? Or just random symbols with the letter 'n' injected at random intervals?

 

[Omnis]

yes n no.