# Line slope calculator 2x+5y=16

**Straight line given by points A[3; 2] and B[8; 0]**

## Calculation:

**Slope-intercept form of line:**y = -0.4x+3.2

**Canonical form of the line equation:**2x+5y-16 = 0

**Parametric form of the line equation:**

x = 5t+3

y = -2t+2 ; t ∈ R

**Slope:**m = -0.4

**Slope angle of line: φ =**-21°48'5″ = -0.3805 rad

**X intercept:**x

_{0}= 8

**Y intercept:**y

_{0}= q = 3.2

**Distance line from the origin:**d

_{0}= 2.9711

**The length of the segment AB: |AB| =**5.3852

**Vector: AB =**(5; -2)

**Normal vector: n =**(2; 5)

**Midpoint of the segment AB: M =**[5.5; 1]

**Perpendicular Bisector equation:**5x-2y-25.5 = 0

**Vector OA = (3; 2) ; |OA| = 3.6056**

**Vector OB = (8; 0) ; |OB| = 8**

**Scalar product OA .OB = 24**

**Angle ∠ AOB = 33°41'24″ = 0.588 rad**